cos^4(t)-sin^4(t)=1-2sin^2(t)

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Solution for cos^4(t)-sin^4(t)=1-2sin^2(t) equation:


Simplifying
cos4(t) + -1sin4(t) = 1 + -2sin2(t)

Multiply cos4 * t
cos4t + -1sin4(t) = 1 + -2sin2(t)

Multiply in4s * t
cos4t + -1in4st = 1 + -2sin2(t)

Multiply in2s * t
cos4t + -1in4st = 1 + -2in2st

Solving
cos4t + -1in4st = 1 + -2in2st

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'in4st' to each side of the equation.
cos4t + -1in4st + in4st = 1 + -2in2st + in4st

Combine like terms: -1in4st + in4st = 0
cos4t + 0 = 1 + -2in2st + in4st
cos4t = 1 + -2in2st + in4st

Divide each side by 'os4t'.
c = o-1s-4t-1 + -2in2o-1s-3 + in4o-1s-3

Simplifying
c = o-1s-4t-1 + -2in2o-1s-3 + in4o-1s-3

Reorder the terms:
c = -2in2o-1s-3 + in4o-1s-3 + o-1s-4t-1

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